a project has a 0.84 chance of doubling your investment in a year and a 0.16 chance of halving your investment in a year. what is the standard deviation of the rate of return on this investment?

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The probability that an investment will double is 0.84, and the probability that it will be halved is 0.16, so the standard deviation of the return on investment will be 0.5499.

Given that there is a 0.84 percent chance that the investment will double and a 0.16 percent chance that it will be half.

We must determine the rate of return on investment's standard deviation.

By calculating the square root of the variance, one can determine the standard deviation.

Suppose the investment is $1.

Probability           Value

0.84                        2

0.16                       0.5

Expected value = Probability * Value

Expected value (EV)  = (0.84 × 2) + (0.16 × 0.5)

EV = 1.68 + 0.08

EV = 1.76

Variance = E(x²) - (Ex)²

V = [(0.84 × 2²) + (0.16 × (0.5)²)] - (1.76)²

V = [(0.84 × 4) + (0.16 × 0.25)] - 3.0976

V = [3.36 + 0.04] - 3.0976

V = 3.4 - 3.0976

V = 0.3024

Standard deviation = [tex]\sqrt{Variance}[/tex]

SD = [tex]\sqrt{0.3024}[/tex]

SD = 0.5499

Hence, the standard deviation of the rate of return on the investment is 0.5499.

Visit the link below to learn more about standard deviation:

brainly.com/question/475676

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