Question

how many total moles of ions are released when the following ionic compound hydrate dissolves completely in water? enter your answer with three decimal places and no units. 84.12 g of mgso4.7h2o

Answer 1

The dissociation of $MgSO_{4}.7H_{2}O$ into ionic compound will release 0.684 moles.

Firstly calculating the number of moles of $MgSO_{4}.7H_{2}O$.

Number of moles = mass ÷ molar mass

Molar mass of magnesium sulphate heptahydrate is 246.48 gram/moles.

Number of moles = 84.12 ÷ 246.48

Performing division

Number of moles = 0.342

As per the known information, the compound $MgSO_{4}.7H_{2}O$ dissociates into

${Mg}^{2 + }$ and ${SO_{4}}^{2 - }$ ions. So, we will get two ions on dissociation of this compound.

Number of ions = 2 × 0.342

Performing multiplication

Number of ions = 0.684

Thus, total 0.684 moles of ions will be released.

Learn more about dissociation -

https://brainly.com/question/305470

#SPJ4