Question

you wish to make a 0.161 m nitric acid solution from a stock solution of 3.00 m nitric acid. how much concentrated acid must you add to obtain a total volume of 175 ml of the dilute solution?

Answer 1

From a stock solution of 3.00 m nitric acid, 9.391 ml of stock solution is needed to create a 0.161 m nitric acid solution, which has a total volume of 175 ml of the diluted solution.

A chemical reagent is present in vast quantities as a stock solution. It has a uniform concentration. Examples of typical stock solutions in laboratories are nitric acid and hydrochloric acid. These play a critical role in creating the titration-related solution preparations.

We know the formula for dilution type problems

             M1 VI = M2 V 2

Where,

M, = initial molarity

V , = initial Volume

M2 = final molarity

V 2 = final Volume

Hene given -

M, = 3.00 M

VI = ?

M2 = 0.161M

V 2 = 175 ml

Accordingly ' MI V1  = M2 V 2

V1 =$(M2*V2)/M1$

V1= (0.161M*175ml)/ 3.00M

v1 = 9.391

The required volume of Stock solution is 9.391ml.

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