50-g iron ball heated to 90 is dropped into a styrofoam cup with 50-g water at 10 c (a) will the final temperature be: between and 50 c, exactly 509c or between 50c and 90c? () calculate final temperature

The quantity of heat required to raise the temperature of one gram of a substance by one Celsius degree is known as Specific Heat. Specific heat is represented by calories or joules per gram per Celsius degree.

The specific heat of water is 1 calorie/gram °C = 4.186 joule/gram °C which is higher than any other common substance. As a result, water plays a very important role in temperature regulation.

What will be the Final Temperature?

Specific heat of the water=4.18j/g degree Celsius

Specific heat of iron=0.450j/g degree Celsius

Let the final temperature be t

-mc(Δt)=mcΔt

m- mass

c- specific heat

Δt- change in temperature

-50×0.450×(t-90)=50×4.18×(t-10)

-22.5t+2025=209t-2090

-22.5t-209t=-2090-2025

231.5t=4115

final temperature=4115÷231.

final temperature=17.7degree Celsius

Therefore ,the final temperature is 17.7 degree Celsius.

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