The equation of the alpha decay of the xenon isotope can be seen to be [tex]\frac{152}{54} Xe ------- > \frac{148}{52}Te + \frac{4}{2} He[/tex]
The term alpha decay has to do with the process by which there is the loss of an alpha particle from a radioactive atom. When there is the loss of an alpha particle, the mass of the parent nucleus would decrease by four and the atomic number would decrease by two units.
Hence, the equation for the decay of the xenon isotope that have been shown by alpha decay is; [tex]\frac{152}{54} Xe ------- > \frac{148}{52}Te + \frac{4}{2} He[/tex]
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