2.802. moles of H₂ can be obtained when 2.802.80 mol hcl reacts with an excess of alal .
The Balance Chemical Equation is as follow,
2 Al + 6 HCl → 3 H₂ + 2 AlCl₃
Calculating moles of H₂ produced,
According to equation,
3.0 moles of HCl produces = 3.0 moles of H₂
So,
2.802.80 moles of HCl will produce = X moles of H₂
Solving for X,
X = (2.802.80 mol × 3.0 mol) ÷ 3 mol
X = 8.4 moles of H₂
When the total number of atoms in the reactants and products sides of a chemical equation equals one, the equation is said to be balanced. In this chemical reaction, hydrogen (H) and nitrogen (N2) combine to create ammonia (NH3). Nitrogen and hydrogen are the reactants, and the end result is ammonia.
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