The concentration of the dilute solution when in the laboratory you dilute 4.59 ml of a concentrated 6.00 m hydrobromic acid solution to a total volume of 175 ml is 0.157 M
Now, using the formula, we get
Substituting the values, we get
M=6.00
V=4.59 mL=4.59x10^-3 L
n=6.00x(4.59x10^-3L)
n=27.54x10^-3 L
The new molarity is Mnew=n/Vnew
Mnew= 27.54x10^-3 V=175 mL=175x10^-3 L
Mnew=27.54x10^-3 mol/175x10^-3 L
Mnew=0.157 M
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