a kite 75ft75ft above the ground moves horizontally at a speed of 4ft/s.4ft/s. at what rate is the angle between the string and the horizontal decreasing when 150ft150ft of string has been let out?

Respuesta :

The angle is decreasing at a rate of 0.0133 radians per second.

The height of the kite from the ground is y = 75 feet.

The kite moves horizontally at a speed of dx/dt = 4 ft/s

The length of the string L = 150 feet

The formula for the sine angle is:

sin ( θ ) = 75/150

sin ( θ ) = 1/2

The horizontal displacement (x) is calculated using the following tangent ratio:

tan θ = 75/x

1 / tanθ = x/75

cot θ = x/75

Differentiating the above equation with respect to t.

- csc² ( θ ) × dθ/dt  = 1/75 × dx/dt

Substituting the values in the equation,

- csc² ( θ ) × dθ/dt  = 1/75 × 4

- csc² ( θ ) × dθ/dt = 4/75

Now,

csc θ = 1/sin θ = 2

So,

- 2² × dθ/dt = 4/75

dθ/dt = - 1/75

dθ/dt = 0.0133

Hence, the angle is decreasing at a rate of 0.0133 radians per second.

Learn more about angle here:

brainly.com/question/27702971

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