We are given the following function
[tex]-12x=380-2y[/tex]Recall that the slope-intercept form is given by
[tex]y=mx+b[/tex]Where m is the slope and b is the y-intercept.
Let us re-write the given function into the slope-intercept form
[tex]\begin{gathered} -12x=380-2y \\ 2y-12x=380 \\ 2y=12x+380 \\ y=\frac{12x+380}{2} \\ y=\frac{12x}{2}+\frac{380}{2} \\ y=6x+190 \end{gathered}[/tex]So, the y-intercept is 190
Note that y-intercept is the point where the line intersects the y-axis
At this point, the x-coordinate is 0
Therefore, the y-intercept written as an ordered pair is
[tex](0,190)[/tex]