Question

6. A sample of carbon dioxide occupies 45 L at 750 K and 2800 mmHg. What is he volume of the gas at STP (0 °C and 1atm)?

Answer 1

Answer:

$V_2\text{ = 60.38 L}$

Explanation:

Here, we want to get the volume of the gas at STP

According to the general gas law, we have it that:

$\frac{P_1V_1}{T_1}\text{ = }\frac{P_2V_2}{T_2}$

where:

P1 is the initial pressure which is 280 mmHg

V1 is the initial volume which is 45 L

T1 is the initial temperature which is 750 K

P2 is the final pressure which is 1 atm (760 mmHg)

V2 is the volume that we want to calculate

T2 is the final temperature (0 degrees celsius is 273.15 K)

Substituting the values, we have it that:

$\begin{gathered} \frac{2800\times45}{750}\text{ = }\frac{760\times V_2}{273.15} \\ \\ V_2\text{ = }\frac{2800\times45\times273.15}{760\times750}\text{ = 60.38 L} \end{gathered}$