From the question;
A technical mechinist is asked to build a cubical steel tank that will hold 220L of water
this implies
[tex]\text{Volume of water = 220L}[/tex]
Using the formula of volume of cube
[tex]\text{volume of cube = l}^3[/tex]
converting Liters to cubic meter
WE have
[tex]220\text{ L = }0.22m^3[/tex]
Hence
[tex]Volumeofcubical-\tan k=0.22m^3[/tex]
Finding the length
[tex]\begin{gathered} l^3=0.22m^3 \\ l=\sqrt[3]{0.22m^3^{}} \\ l=0.604m \end{gathered}[/tex]
Hence the smallest possible inside length of the cubical tank is 0.604m
