If APML - ATRQ, find QR.P35_MQT7x - 92x + 214RLA O 1.58B.17C.5.16D.16

Since it is given that two triangles are similar so
[tex]\begin{gathered} \frac{35}{7x-9}=\frac{14}{2x+2} \\ \frac{5}{7x-9}=\frac{2}{2x+2} \\ 10x+10=14x-18 \\ 4x=28 \\ x=7 \end{gathered}[/tex]So the correction option is (B)