Question

(a) The trinomial 492 – 147 + I is in the form o? - 2ab + 62, where a =andoand be(b) Use the formula 32 - 2ab + b2 = (a - b) to factor 49y2 - 14y + 1.49} – 198+1=(Additional Materials

Answer 1

Simplify the equation 49y^2 - 14y + 1 to obtain in form of a^2 - 2ab + b^2.

$49y^2-14y+1=(7y)^2-2\cdot7y\cdot1+(1)^2$

So value of a = 7y and b = 1.

(b)

The formula for a^2 - 2ab + b^2 is,

$a^2-2ab+b^2=(a-b)^2$

So equation after completing the square,

$\begin{gathered} 49y^2-14y\cdot1+1^{}=(7y)^2-2\cdot7y\cdot1+(1)^2 \\ =(7y-1)^2 \end{gathered}$

So answer is,

$49y^2-14y+1=(7y-1)^2$