Question

11) Joni, who is 5 feet tall,is walking to her officebuilding which she knows is 150ft high. The angle to the top ofthe building from the top of herhead is 6º. How much furtherdoes she need to walk?

Answer 1

Step 1: Angle of elevation

Step 2 : Using SOHCAHTOA

$\begin{gathered} \text{Height of the building = 150ft} \\ \text{distance to the building = x} \\ \text{angle of elevation = 6}^{\circ} \\ \text{from SOHCAHTOA } \\ Tan\text{ }\theta\text{ = }\frac{\text{Opposite}}{\text{Adjacent}} \\ Tan6^0=\text{ }\frac{150ft}{x} \\ x\text{ = }\frac{150ft}{\tan 6^0} \\ x\text{ = }\frac{150ft}{0.105} \\ x\text{ = 1428.5ft} \\ \end{gathered}$

Hence the distance she need to work = 1428.5 ft