Solution
[tex]\begin{gathered} (sec\text{ V+tan V\rparen}^2=\frac{1+sinV}{1-sin\text{ v}} \\ from\text{ the left hand side} \\ (\frac{1}{cosv}+\frac{sinv}{cosv})^2 \\ \\ \\ =(\frac{1+sinv}{cosV})^2=\frac{(1+sinv)^2}{(1-sin^2v)}=\frac{(1+sinv)(1+sinv)}{(1+sinv)(1-sinv)} \\ \\ Cross\text{ the common factor \lparen1+sinv\rparen} \\ \\ \\ \frac{1+sinv}{1-sinv} \end{gathered}[/tex]
