Question

The perimeter of a rectangle is 22 inches. If the length of the rectangle is one inch less than two times the width, find the dimensions

Answer 1

We know that the perimeter is 22 inches.

Also, the length is one inch less than two times the width, which means

$l=2w-1$

Then, we use the perimeter formula

$\begin{gathered} P=2(w+l) \\ 22=2(w+2w-1) \\ \frac{22}{2}=3w-1 \\ 11=3w-1 \\ 3w=11+1 \\ w=\frac{12}{3} \\ w=4 \end{gathered}$

Then, we find the length

$l=2\cdot4-1=8-1=7$

Hence, the dimensions are 4 inches wide and 7 inches long.