To solve for x, first multiply the terms to remove the brackets
[tex]\begin{gathered} 6+3x=5(x-1)-3(x-2) \\ 6+3x=5x-5-3x-(2)(-3) \\ 6+3x=5x-5-3x+6 \\ 6+3x=5x-3x+1 \end{gathered}[/tex]
Now bring all the x terms to LHS
[tex]\begin{gathered} 3x+3x-5x=1-6 \\ 6x-5x=-5 \\ x=-5 \end{gathered}[/tex]
Hence the value of x is -5
