y = 3/5
Explanation:[tex]y^{3}=\frac{27}{125}[/tex]we would find the cube root of both sides:
[tex]\sqrt[3]{y^3}\text{ = }\sqrt[3]{\frac{27}{125}}[/tex][tex]\begin{gathered} y\text{ = }\sqrt[3]{\frac{3^3}{5^3}}=\frac{\sqrt[3]{3^3}}{\sqrt[3]{5^3}} \\ y\text{ = 3/5} \end{gathered}[/tex]