Okay, here we have this:
Considering the provided information, we are going to calculate the volumen of the conical tent, so we obtain the following:
[tex]\begin{gathered} V=\frac{1}{3}h\cdot\pi\cdot r^2 \\ =\frac{1}{3}(4.8)\cdot\pi\cdot(4.8)^2 \\ \approx115.81 \end{gathered}[/tex]Now, let's try doubling the radius, to see what happens to the volume:
[tex]\begin{gathered} =\frac{1}{3}(4.8)\cdot\pi\cdot(9.6)^2 \\ \approx463.24 \end{gathered}[/tex]Finally we obtain that doubling the radius quadruples the volume, therefore the correct answer is the third option.