Answer:
12. y = 3x + 5
Explanation:
Two lines are parallel if they have the same slope.
In an equation of the form y = 3x + 1, the equation is the number beside the x, so the slope is 3. Then our line will have a slope of 3 and pass through the point (-1, 2).
The equation of a line with slope m that passes through the point (x1, y1) is
[tex]y-y_1=m(x-x_1)[/tex]
Replacing m = 3 and (x1, y1) = (-1, 2), we get:
[tex]\begin{gathered} y-2=3(x-(-1_{})) \\ y-2=3(x+1) \end{gathered}[/tex]
To write in slope-intercept form, we need to solve the equation for y, so
[tex]\begin{gathered} y-2=3(x)+3(1) \\ y-2=3x+3 \\ y-2+2=3x+3+2 \\ y=3x+5 \end{gathered}[/tex]
So, the answer for question 12 is y = 3x + 5
