Respuesta :

Given the equation of a circle:

[tex](x+15)^2+(y-21)^2=81[/tex]

You need to remember thatthe equation of a circle has this form:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

Where "h" is the x-coordinate of the center of the circle, "k" is the y-coordinate of the center , and "r" is the radius.

In this case, you can identify that:

[tex]\begin{gathered} h=-15 \\ k=21 \end{gathered}[/tex]

Notice that:

[tex]r^2=81[/tex]

Solving for "r", you get:

[tex]\begin{gathered} r=\sqrt{81} \\ r=9 \end{gathered}[/tex]

Hence, the answer is:

- The coordinates of the center of the circle are:

[tex](-15,21)[/tex]

- The radius of the circle is:

[tex]9[/tex]

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