Step 1
Given;
[tex]\begin{gathered} 4x-3y=12--(1) \\ 7x-3y=3---(2) \end{gathered}[/tex]Step 2
Subtract equation 2 from 1
Hence,
[tex]\begin{gathered} -3x=9 \\ -\frac{3x}{-3}=\frac{9}{-3} \\ x=-3 \end{gathered}[/tex]Find the value y using equation 1
[tex]\begin{gathered} 4(-3)-3y=12 \\ -12-3y=12 \\ -12-12=3y \\ \frac{3y}{3}=-\frac{24}{3}=-8 \end{gathered}[/tex]x=-3 and y=-8