Question

Graph the function. Which choice gives the aptitude,Phase shift, and vertical shift for the function

Answer 1

The given function is:

$y=4\sin\lparen3\theta-\frac{1}{3}\pi)+1$

Therefore, the parent function is:

$y=\sin(\theta)$

The graph of the given function is:

Therefore, the period is given by:

$\frac{2\pi}{3}$

The amplitude is given by:

$|4|=4$

$y=4\sin\lparen3(\theta-\frac{1}{9}\pi))+1$

The phase shift is:

$\frac{1}{9}\pi=\frac{\pi}{9}$

The vertical shift is 1

The correct answer is:

4; 2π/3; π/9; 1

Therefore, the correct answer is the second choice.