Question

5 8. The toy car traveled 3 cm north, 8 cm east, 2 cm south, 4 cm east. 3 cm south, and finally 12 cm west. Distance = Displacement 9. The toy car traveled 6 cm south, 7 cm east. 2 cm south, 3 cm east. 6 cm north, and finally 10 cm west. Distance = Displacement : 10. The toy car traveled 5 cm west, 10 cm south. 3 cm east. 3 cm south, 2 cm east, 13 cm north, and finally 2 cm west Distance = Displacement - uce the Pythagorean Theorem

Answer 1

Answer:

Question 8:

Distance: 32cm

Displacement: 2 cm south

Question 9:

Distance: 34cm

Displacement : 2 cm south

Question 10:

Distance: 38 cm

Displacement: 2 cm west

Explanation:

Distance is defined as the total length of the path followed when getting from point A to point B.

Displacement is defined as the straight line distance between point A and point B.

Now, the distance the toy car travelled is

$3\operatorname{cm}+8\operatorname{cm}+2\operatorname{cm}+4\operatorname{cm}+3\operatorname{cm}+12\operatorname{cm}=32\operatorname{cm}\text{.}$

The displacement of the toy is represented in the diagram below:

From the diagram, we see that the displacement of the toy car is 2 cm south .

Question 9.

The distance travelled by the toy car is

$6\operatorname{cm}+7\operatorname{cm}+2\operatorname{cm}+3\operatorname{cm}+6\operatorname{cm}+10\operatorname{cm}=34\operatorname{cm}$

The displacement of the toy is represented by the diagram below.

As can be seen from the diagram, the displacement of the toy car is 2 cm south .

Question 10.

The distance travelled by the toy car is

$5\operatorname{cm}+10\operatorname{cm}+3\operatorname{cm}+3\operatorname{cm}+2\operatorname{cm}+13\operatorname{cm}+2\operatorname{cm}=38\operatorname{cm}$

The displacement of the toy car can be found by considering the diagram below.

As can be seen in the diagram above, with all the movement of the toy, it travelled only 2 cm west from its initial position. Hence, the displacement of the toy car is 2 cm west.