The sum of internal angles of a convex polygon is = (n-2)* 180º
n= number of sides
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Decangon n = 10
(10 -2)* 180º
8* 180º
The sum of internal angles of this convex polygon is = 1440
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n= 16
(16 -2)* 180º
14* 180º
The sum of internal angles of this convex polygon is = 2520
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n =30
(30 -2)* 180º
28* 180
The sum of internal angles of this convex polygon is = 5040
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n = 8
(8 -2)* 180º
6* 180
The sum of internal angles of this convex polygon is = 1080
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