We have the inequality
[tex]3x>105[/tex]To solve we notice that the 3 multiplying x is positive, so we can divide both sides of the inequality by 3 without changing the sign. Then
[tex]\begin{gathered} 3x>105 \\ \frac{3x}{3}>\frac{105}{3} \\ x>35 \end{gathered}[/tex]In interval notation this is
[tex](35,\infty)[/tex]