Question

which of the following logarithmic equations is equivalent to the exponential equation below? 7^x=49

Answer 1

Solution

- The solution steps are given below:

$\begin{gathered} 7^x=49 \\ \text{ Take the logarithm to base 7, of both sides} \\ \log_77^x=\log_749 \\ \\ \text{ Recall that, } \\ \log_aa^b=b \\ \\ \therefore\log_77^x=x=\log_749 \\ \\ \text{ Thus, the answer is:} \\ \\ \log_749=x\text{ \lparen OPTION D\rparen} \end{gathered}$