100, 110, 120, 130, (Use the equation an= a1 + (n - 1)d
step 1
Find the common difference d
we have
a1=100
a2=110
a3=120
a4=130
so
a2-a1=110-100=10
a3-a2=120-110=10
a4-a3=130-120=10
the common difference d is equal to 10
d=10
step 2
substitute in teh formua
[tex]\begin{gathered} a_n=a_1+(n-1)\cdot d \\ we\text{ have} \\ a_1=100 \\ d=10 \\ \text{substitute} \\ a_n=100+(n-1)\cdot10 \\ a_n=100+10n-10 \\ a_n=90+10n \end{gathered}[/tex]If you want to calculate the a7 term
then
For n=7
substitute in the formula
[tex]\begin{gathered} a_7=90+10\cdot7 \\ a_7=160 \end{gathered}[/tex]