Question

Study the spinner below. If the wedges 2 and 5 are twice the area of the otherwedges what is the likelihood of landing on 4 or 6?23416/5A.NIO.B.A-OC.100oD. There is not enough information provided.

Answer 1

As we can see, there are 8 parts in our circle but 4 parts belong to wedge 2 and 5. Then, the probability of landing on 4 or 6 is given by

$P(4\cup5)=P(4)+P(5)$

because part 4 and part 5 are disjoint sets. Since there are 8 parts in our circle, we have

$\begin{gathered} P(4\cup5)=P(4)+p(5) \\ P(4\cup5)=\frac{1}{8}+\frac{1}{8} \end{gathered}$

which gives

$P(4\cup5)=\frac{2}{8}=\frac{1}{4}$

which corresponds to option B