Respuesta :

Given the figure of a square pyramid

The area pf the base =area of the square of side 14 in =

[tex]14\cdot14=196in^2[/tex]

the area of the sides = 4 times the area of a triangle of a base of 14 in and a height of 12 in

so, the area of the sides =

[tex]4\cdot\frac{1}{2}\cdot\text{base}\cdot\text{height}=4\cdot\frac{1}{2}\cdot14\cdot12=336in^2[/tex]

So, the surface area of the pyramid =

[tex]196+336=532in^2[/tex]

So, the answer will be A = 532 in^2

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