[tex]\begin{gathered} \text{Now, } \\ \angle ABD+\angle CDB=180º \\ (7x-31)+(4x+5)=180 \\ 11x+(5-31)=180º \\ 11x-26=180 \\ 11x=180+26 \\ 11x=206 \\ x=\frac{206}{11}\approx18.72 \end{gathered}[/tex][tex]\begin{gathered} \text{ Thus } \\ \angle ABD=7(18.72)-31 \\ =100.09 \end{gathered}[/tex]