What does the constant 0.35 reveal about the rate of change of the quantity?


ANSWER:
EXPLANATION:
Given:
[tex]f(t)=640(0.35)^{60t}[/tex]Recall that an exponential decay function is generally given as;
[tex]f(t)=a(1-r)^t[/tex]where;
a = initial amount = 640
r = rate of decrease
t = time
We can go ahead and find r as seen below;
[tex]\begin{gathered} 1-r=0.35 \\ -r=0.35-1 \\ r=-0.35+1 \\ r=0.65 \\ r=0.65*100 \\ r=65\text{\%} \end{gathered}[/tex]So we have that the function is decaying exponentially at a rate of 65% every hour