Question:
Solution:
Let the expression:
[tex]\frac{-5\text{ + 7i}}{3-i}[/tex]this expression is equivalent to:
[tex]\frac{-5\text{ + 7i}}{3-i}\text{ x }\frac{3+i}{3+i}\text{ }[/tex]that is
[tex]=\text{ }\frac{(-5+7i)(3+i)}{(3-i)(3+i)}\text{ = }\frac{-22+16i}{10}[/tex]this is equivalent to:
[tex]=\text{ }\frac{-22+16i}{10}\text{ = }\frac{-22}{10}\text{ + }\frac{16}{10}i\text{ }[/tex]then, we can conclude that the correct answer is:
[tex]=\text{ }\frac{-22}{10}\text{ + }\frac{16}{10}i\text{ }[/tex]that is:
[tex]=-2.2\text{ + 1.6}i\text{ }[/tex]