A company produces optical-fiber cable with a mean of 0.3 flaws per 100 feet. What is the probability that there will be exactly 5 flaws in 1000 feet of cable? Round your answer to four decimal places.

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Step 1

Given; A company produces optical-fiber cable with a mean of 0.3 flaws per 100 feet. What is the probability that there will be exactly 5 flaws in 1000 feet of cable? Round your answer to four decimal places.

Step 2

Let X denote the number of flaws in the optical cable.

The mean number of flaws per 100 feet =0.3

Thus the mean number of flaws per 1000 feet is;

[tex]\lambda=0.3\times\frac{1000}{100}=0.3\times10=3[/tex][tex]_^{X\approx P(3)}[/tex]

Applying the formula

[tex]P(X=x)=\frac{e^{-\lambda}(\lambda)^x}{x!}[/tex][tex]\begin{gathered} P(X=x)=\frac{e^{-3}(3)^5}{5!} \\ x=5 \\ P(X=5)=0.1008 \end{gathered}[/tex]

Answer;

[tex][/tex]

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