Step 1
Given; A company produces optical-fiber cable with a mean of 0.3 flaws per 100 feet. What is the probability that there will be exactly 5 flaws in 1000 feet of cable? Round your answer to four decimal places.
Step 2
Let X denote the number of flaws in the optical cable.
The mean number of flaws per 100 feet =0.3
Thus the mean number of flaws per 1000 feet is;
[tex]\lambda=0.3\times\frac{1000}{100}=0.3\times10=3[/tex][tex]_^{X\approx P(3)}[/tex]Applying the formula
[tex]P(X=x)=\frac{e^{-\lambda}(\lambda)^x}{x!}[/tex][tex]\begin{gathered} P(X=x)=\frac{e^{-3}(3)^5}{5!} \\ x=5 \\ P(X=5)=0.1008 \end{gathered}[/tex]Answer;
[tex][/tex]