SOLUTION
a)
[tex]\begin{gathered} mAB=60^o \\ (As\text{ seen in the figure)} \end{gathered}[/tex]b)
[tex]\begin{gathered} \text{mBC}=360-(60+90+90) \\ \text{mBC}=360-(240) \\ \text{mBC}=120^o \end{gathered}[/tex]c)
[tex]\begin{gathered} \text{mBEC}=60+90+90 \\ \text{mBEC}=240^o \end{gathered}[/tex]d)
[tex]\begin{gathered} m\angle MCF=90^o \\ (\text{When a radius meets a tangent, the angle formed is 90 degrees)} \end{gathered}[/tex]e)
[tex]\begin{gathered} m\angle EMD=m\angle EMC-m\angle DMC \\ m\angle EMD=90^o-60^o \\ m\angle EMD=30^o \end{gathered}[/tex]