Question

10. In OK, JL LM, KN = 3x - 2,and KP= 2x + 1. What is ?LNP.KM

Answer 1

$\begin{gathered} JL\cong KN \\ \text{Hence} \\ KN\cong KP \\ \text{Therefore} \\ 3x-2=2x+1 \\ \text{Solving x} \\ 3x-2x=1+2 \\ x=3 \\ The\text{ value of x is 3} \\ \end{gathered}$