[tex]\begin{gathered} \frac{4}{3} \\ \\ \frac{4}{5} \\ \\ \frac{3}{5} \end{gathered}[/tex]
1) Examining that triangle, we can write out the following trigonometric ratios:
[tex]\begin{gathered} \tan(A)=\frac{opposite\:leg}{adjacent\:leg}=\frac{4}{3} \\ \\ \sin(A)=\frac{opposite\:leg}{hypotenuse}=\frac{4}{5} \\ \\ \cos(A)=\frac{adjacent\:leg}{hypotenuse}=\frac{3}{5} \end{gathered}[/tex]
Note that these ratios refer to the angle A.
