we are asked to determine the kinetic energy of an object that has a mass of 4.96g. To do that we will use the following formula:
[tex]K=\frac{1}{2}mv^2[/tex]Where:
[tex]\begin{gathered} K=\text{ kinetic energy }\lbrack J\rbrack \\ m=\text{ mass }\lbrack kg\rbrack \\ v=\text{ velocity }\lbrack\frac{m}{s}\rbrack \end{gathered}[/tex]First, we will convert the mass into kilograms using the following conversion factor:
[tex]1\operatorname{kg}=1000g[/tex]Now we multiply the mass by the conversion factor in decimal form:
[tex]4.96g\times\frac{1\operatorname{kg}}{1000g}=0.00496\operatorname{kg}[/tex]Now, we convert the velocity into meters per second by converting kilometers into meters. To do that we will use the following conversion factor:
[tex]1\operatorname{km}=1000m[/tex]Now, we multiply the velocity by the conversion factor:
[tex]49.1\frac{\operatorname{km}}{s}\times\frac{1000m}{1\operatorname{km}}=49100\frac{m}{s}[/tex]Now, we substitute the values in the formula for the kinetic energy:
[tex]K=\frac{1}{2}(0.00496)(49100\frac{m}{s})^2[/tex]Solving the operations:
[tex]K=5.99\times10^6J[/tex]And thus we have determined the kinetic energy of the meteorite.