[tex]\begin{gathered} W=(4,4) \\ X=(6,2) \\ Y=(-8,16) \\ \text{Let:} \\ (x1,y1)=(4,4) \\ (x2,y2)=(6,2) \end{gathered}[/tex][tex]\begin{gathered} m=\frac{y2-y1}{x2-x1}=\frac{2-4}{6-4}=-\frac{2}{2}=-1 \\ y-y1=m(x-x1) \\ y-4=-1(x-4) \\ y-4=-x+4 \\ y=-x+8 \\ (-8,16) \\ 16=-(-8)+8 \\ 16=16 \end{gathered}[/tex]
Therefore, they are collinear
