Question

what is simplified form of 7x^2y^3/28xy

Answer 1

$\frac{7x^2y^3}{28xy}$

Divide 7 by 28:

7/28 = 1/4

To divide the variables, subtract the exponents:

$x^{(2-1)}y^{(3-1)}=x^1y^2=xy^2$

SO, the final expression is:

$\frac{1}{4}xy^2=\frac{xy^2}{4}$