Question

determine the magnitude of the current flowing through a 10 ms conductance if the voltage across it is (a) 2 mv; (b) −1 v; (c) 100e−2t v; (d) 5 sin(5t) v; (e) 0 v

Answer 1

Magnitude of the current flowing through a 10 ms conductance will be  20 uA , -10 mA,  e-²t ampere, 0.05sin(5t) ampere and 0  if the voltage are given.

Conductance G = 10mS

Reactance X = 1/G

X = 1/10mS = 100 ohm

(a)

For 2 mV,

I = 2mV/100 = 20 uA

(b)

For  -1 Volt

I = (-1)/100 = -10 mA

(C)

For V = 100e-²t

I = (100e-²t)/100 = e-²t ampere

(d)

For V = 5sin(5t)

I = (5sin(5t))/100 = 0.05sin(5t) ampere

(e)

For V = 0

I = 0/100 = 0 ampere

Charge flow is what makes up current. The quantity of charge flowing through a conductor at any one moment determines the instantaneous current.

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