Answer:
Completing the table, we have;
Explanation:
Given that the number of beetles after x weeks can be determined using the equation;
[tex]P(x)=25\ast2^x[/tex]
Let us substitute to complete the table;
[tex]\begin{gathered} at\text{ x=0} \\ P(0)=25\ast2^0=25\times1 \\ P(0)=25 \end{gathered}[/tex][tex]\begin{gathered} at\text{ x=1;} \\ P(1)=25\ast2^1=25\times2 \\ P(1)=50 \end{gathered}[/tex][tex]\begin{gathered} at\text{ x=2;} \\ P(2)=25\ast2^2=25\times4 \\ P(2)=100^{} \end{gathered}[/tex][tex]\begin{gathered} at\text{ x=3;} \\ P(3)=25\ast2^3=25\times8 \\ P(3)=200 \end{gathered}[/tex][tex]\begin{gathered} at\text{ x=4;} \\ P(4)=25\ast2^4=25\times16 \\ P(4)=400 \end{gathered}[/tex][tex]\begin{gathered} at\text{ x=5;} \\ P(5)=25\ast2^5=25\times32 \\ P(5)=800 \end{gathered}[/tex]
Completing the table, we have;