Given data:
* The speed of the water coming out of the pipe is,
[tex]v_1=14.9\text{ m/s}[/tex]
* The diameter of the left side of pipe is,
[tex]d_2=8\text{ cm}[/tex]
* The diameter of the right side of the pipe is,
[tex]d_1=2\text{ cm}[/tex]
Solution:
(a). The area of the right side of pipe is,
[tex]A_1=\pi r^2_1[/tex]
The radius of the right side of pipe is,
[tex]\begin{gathered} r_1=\frac{d_1}{2} \\ r_1=\frac{2}{2} \\ r_1=1\text{ cm} \end{gathered}[/tex]
Thus, the area of the right side of pipe is,
[tex]\begin{gathered} A_1=\pi\times(1\times10^{-2})^2 \\ A_1=\pi\times(0.01)^2 \\ A_1=0.000314m^2 \end{gathered}[/tex]
The volume of the water coming out from the right side of the pipe is,
[tex]V=v_1t\times A_1[/tex]
Where t is the time taken, v_1 is the velocity of the water, and A_1 is the area of right side of pipe,
Substituting the known values,
[tex]\begin{gathered} V=14.9\times7\times60\times0.000314 \\ V=1.97m^3 \end{gathered}[/tex]
Thus, the volume of water flows into the atmosphere is 1.97 meter cube.
