Question

I need help to find the indicated operation:h(t)=-2t-3g(t)=t^2+3tFind (2t^2+2t)(-4t)

Answer 1

The value of (2h+2g)(t) can be determined as,

$\begin{gathered} (2h+2g)(t)=2h(t)+2g(t) \\ =2\lbrack h(t)+g(t)\rbrack \\ =2\lbrack-2t-3+t^2+3t\rbrack \\ =2\lbrack t^2+t-3\rbrack \\ =2t^2+2t-6 \end{gathered}$