Question

I'd love some help on this, and I'm actually in quite the hurry so if you could be fast that would be most helpful?

Answer 1

Step 1

Given;

Step 2

We know that the measure of the interior angle is the half sum of the arcs comprising it and its opposite

so

$m\angle CED=\frac{1}{2}(arc\text{ AB + arc CD\rparen}$$\begin{gathered} arc\text{ AB=82} \\ arc\text{ CD=48} \\ m\angle CED=\frac{1}{2}(82+48) \end{gathered}$

Answer;

$m\angle CED=65^o$