What is the solution to |x – 2| + 3 > 17?A. x < –12 or x > 16B. x < –14 or x > 7C. –12 < x < 16D. –14 < x < 7

Solve the equation:
[tex]|x-2|+3>17[/tex]Subtracting 3 on both sides of the inequality:
[tex]|x-2|>14[/tex]The solutions to this inequality come from the following conditions:
[tex]\begin{gathered} x-2>14 \\ \\ OR \\ \\ x-2\lt-14 \end{gathered}[/tex]Adding 2 to both inequalities:
[tex]\begin{gathered} x>16 \\ \\ OR \\ \\ x\lt-12 \end{gathered}[/tex]Answer: First choice