The figure shows the graph of f(x)=4+x/x+3, along with it's tangent line at the point (0,4). What is f'(0)?

Since we know the tangen line:
[tex]y=\frac{1}{3}x+4[/tex]then f ^prime evaluated at zero is the same as evaluate this last equation at x=0, that is,
[tex]f\text{´}(0)=\frac{1}{3}(0)+4[/tex]which gives
[tex]f^{\prime}(0)=4[/tex]then, the answer is 4.
Lets compute the derivative of our given function:
then, f^prime at zero is equal to
then, the answer is 1/3. Then, the given line doesnt correspond with the derivative at x=0