Question

if cos B is 6/13 what is sin a

Answer 1

ok

Find x

$\begin{gathered} \text{ x}^2=13^2-6^2 \\ \text{ x}^2\text{ = 169 - 36} \\ x^2\text{ = 133} \\ x\text{ = }\sqrt[]{133} \end{gathered}$

$\text{ sin A = }\frac{6}{13}$

cos B = sin A