Question

Tom went to the park on a windy day to fly his kite. He released 40 feet of string at an angle of elevation of 360. How high is his kite in the air?

Answer 1

Answer: 0 ft

First, let us illustrate the problem.

Since the angle of elevation is 360 degrees, this would mean that the kite is on the ground. Therefore, the kite is 0 ft high.

To show this through computation:

$\begin{gathered} \sin 360=\frac{x}{40} \\ x=0 \end{gathered}$