Respuesta :
Answer:
[tex]\begin{gathered} \%Mg=20.19\% \\ \%S=26.64\% \\ \%O=53.17\% \end{gathered}[/tex]Explanations
The chemical compound for magnesium sulfate is given as MgSO₄.
Given the following known parameters:
Molar mass of magnesium = 24.305 g/mol
Molar mass of sulfur = 32.065 g/mol
Molar mass of oxygen = 16.00g/mol
The molar mass of magnesium sulfate is calculated as shown below:
[tex]\begin{gathered} \text{Molar mass of MgSO}_4=24.305+32.065+4(16.00) \\ \text{Molar mass of MgSO}_4=120.37g\text{/mol} \end{gathered}[/tex]Determine the percent composition by mass of Magnesium
[tex]\begin{gathered} \%Mg=\frac{Molar\text{ mass of Mg}}{120.37}\times100 \\ \%Mg=\frac{24.305}{120.37}\times100 \\ \%Mg=0.2019\times100 \\ \%Mg=20.19\% \end{gathered}[/tex]For the percent composition by mass of sulfur:
[tex]\begin{gathered} \%S=\frac{Molar\text{ mass of S}}{120.37}\times100 \\ \%S=\frac{32.065}{120.37}\times0 \\ \%S=0.2664\times100 \\ \%S=26.64\% \end{gathered}[/tex]For the percent composition by mass of oxygen
[tex]\begin{gathered} \%O=\frac{Molar\text{ mass of O}}{120.37}\times100 \\ \%O=\frac{64.0}{120.37}\times100 \\ \%O=0.5317\times100 \\ \%O=53.17\% \end{gathered}[/tex]
